5.2 Given a (decimal – e.g. 3.72) number that is passed in as a string, print the binary representation If the number can not be represented accurately in binary, print “ERROR”

/*
Background:
0.5 = 0.1
0.25 = 0.01
0.125 = 0.001
0.0625 = 0.0001
So:
0.8125 = 0.5 + 0.25 + 0.0625 = 0.1 + 0.01 + 0.0001 = 0.1101
*/

#include <iostream>
#include <string>
#include <cstdlib>
#include <algorithm>
#include <cstring>

using namespace std;

int main()
{
    double input = atof("2312313.8125");
    
    int    i = input;
    double d = input - i;
    
    string left;
    while (i != 0)
    {
        left.append(1, i % 2 + '0');
        i = i / 2;
    }
    reverse(left.begin(), left.end());
    
    string right;
    double e = 0.00000001;
    //while (d < 0 - e || d > e - 0)
    while (d - 0 > e - 0) //distance from 0
    {
        if (right.size() > 10)
        {
            cout << "ERROR" << endl;
            return 1;
        }
        d = d * 2;
        
        if (d > 1 || (d > 1 - e && d < 1 + e)) //critical
        {
            right.append(1, '1');
            d = d - 1;
        }
        else
        {
            right.append(1, '0');
        }
    }
    
    
    cout << left << '.' << right << endl;
    return 0;
}